python之Django Rest Framework 实现多对多关系_编程设计

我想实现一个多对多关系，这样一个人可以加入多个社交俱乐部，一个社交俱乐部可以有多个成员。这是我得到的结果，但它不显示电影详细信息，序列化给我一个错误 -
原始异常文本为:“ManyRelatedManager”对象没有属性“club_name”。

模型.py

class Club(models.Model): 
  club_name = models.CharField(default='',blank=False,max_length=100) 
 
class Person(models.Model): 
  person_name = models.CharField(default='',blank=False,max_length=200) 
  clubs = models.ManyToManyField(Club)

serializers.py

class ClubSerializer(serializers.ModelSerializer): 
  class Meta: 
    model = Club 
    fields = ('url','id','club_name','person') 
 
class PersonSerializer(serializers.ModelSerializer): 
  clubs = ClubSerializer() 
  class Meta: 
    model = Person 
    fields = ('url','id','person_name','clubs')

views.py

class ClubDetail(generics.ListCreateAPIView): 
serializer_class = ClubSerializer 
 
  def get_queryset(self): 
    club = Clubs.objects.get(pk=self.kwargs.get('pk',None)) 
    persons = Person.objects.filter(club=club) 
    return persons 
 
class ClubList(generics.ListCreateAPIView): 
  queryset = Club.objects.all() 
  serializer_class = ClubSerializer 
 
 
class PersonDetail(generics.RetrieveUpdateDestroyAPIView): 
  serializer_class = PersonSerializer 
 
 
def get_object(self): 
  person_id = self.kwargs.get('pk',None) 
  return Person.objects.get(pk=person_id)

urls.py

urlpatterns = format_suffix_patterns([ 
url(r'^$', views.api_root), 
url(r'^clubs/$', 
views.ClubList.as_view(), 
name='club-list'), 
url(r'^clubs/(?P<pk>[0-9]+)/persons/$', 
views.ClubDetail.as_view(), 
name='club-detail'), 
url(r'^person/(?P<pk>[0-9]+)/$', 
views.PersonDetail.as_view(), 
name='person-detail'), 
])

在我的本地服务器上，我得到了俱乐部列表，该列表将我导航到俱乐部详细信息 View ，但它不显示电影名称，或者，但我看不到人员列表。我该如何正确执行此操作？

请您参考如下方法:

您的代码中存在许多问题。即:

ClubSerializer.Meta.fields - person 应该是 person_set
PersonSerializer - 俱乐部应该是 clubs = ClubSerializer(many=True)
ClubDetail.serializer_class - ClubSerializer 应该是 PersonSerializer
ClubDetail - 查询集应该是 persons = Person.objects.filter(clubs=club)

如果您解决了上述问题，您应该能够导航到 ClubDetail 并查看俱乐部成员列表。