我一直在努力通过 Python 中的正则表达式拆分我的字符串。
我加载了一个文本文件，格式为:
"Peter went to the gym; \nhe worked out for two hours \nKyle ate lunch
at Kate's house. Kyle went home at 9. \nSome other sentence
here\n\u2022Here's a bulleted line"
我想得到以下输出:
['Peter went to the gym; he worked out for two hours','Kyle ate lunch
at Kate's house. He went home at 9.', 'Some other sentence here',
'\u2022Here's a bulleted line']
我想用 Python 中的换行符和大写字母或项目符号分隔我的字符串。
我已经尝试解决问题的前半部分，将我的字符串拆分为一个新行和大写字母。
这是我目前所拥有的:
print re.findall(r'\n[A-Z][a-z]+',str,re.M)
这只是给我:
[u'\nKyle', u'\nSome']
这只是第一个词。我尝试了该正则表达式的变体，但我不知道如何获取该行的其余部分。
我假设为了也按要点拆分，我只包含一个 OR 正则表达式，其格式与按大写字母拆分的正则表达式相同。这是最好的方法吗？
我希望这是有道理的，如果我的问题无论如何都不清楚，我很抱歉。 :)
请您参考如下方法:
您可以使用这个split 函数:
>>> str = u"Peter went to the gym; \nhe worked out for two hours \nKyle ate lunch at Kate's house. Kyle went home at 9. \nSome other sentence here\n\u2022Here's a bulleted line"
>>> print re.split(u'\n(?=\u2022|[A-Z])', str)
[u'Peter went to the gym; \nhe worked out for two hours ',
u"Kyle ate lunch at Kate's house. Kyle went home at 9. ",
u'Some other sentence here',
u"\u2022Here's a bulleted line"]
