我需要制作一个tensorflow中没有的激活函数,我该怎么办?我见过这个链接, How to make a custom activation function with only Python in Tensorflow? 但我仍然不知道如何实现图片中的新型激活功能。 relu,leaky_relu and a new type of relu
请您参考如下方法:
我认为这个可以为您服务。我只使用了包含 tensorflow 的函数,他负责管理反向传播。
如果您使用 python 函数,则必须同时对前向和后向进行编程。但问题是当您必须将分段函数的函数掩码保存在“缓存”中时(我个人不知道它是如何完成的,如果知道的话会很有趣)。
import numpy as np
import tensorflow as tf
def new_relu(x, k=0.2):
part_1 = tf.to_float(tf.math.less_equal(0.0, x))
part_2 = tf.to_float(tf.math.logical_and(tf.math.less_equal(-1.0, x), tf.math.less(x, 0.0)))
part_3 = tf.to_float(tf.math.less(x, -1.0))
return part_1*x + part_2*x*k #+ part_3*0
def new_relu_test():
# create data
x = tf.random_normal([10])*10000
y = new_relu(x)
with tf.Session():
diff = tf.test.compute_gradient_error(x, [10], y, [10])
print(diff)
# use in dense
x = tf.placeholder(shape=[None, 3], dtype=tf.float32)
nn = tf.layers.dense(x, 3, activation=new_relu)
编辑: 如果您希望第二个参数也是张量,则必须与输入大小相同。
import numpy as np
import tensorflow as tf
def new_relu(x, k=0.2):
part_1 = tf.to_float(tf.math.less_equal(0.0, x))
part_2 = tf.to_float(tf.math.logical_and(tf.math.less_equal(-1.0, x), tf.math.less(x, 0.0)))
part_3 = tf.to_float(tf.math.less(x, -1.0))
return part_1*x + part_2*x*k #+ part_3*0
def new_relu_test():
# create data
x = tf.random_normal([10])*10000
y = new_relu(x)
with tf.Session():
diff = tf.test.compute_gradient_error(x, [10], y, [10])
print(diff)
# use in dense
x = tf.placeholder(shape=[None, 3], dtype=tf.float32)
x_b = tf.placeholder(shape=[None], dtype=tf.float32)
nn_1 = tf.layers.dense(x, 3)
nn_2 = tf.layers.dense(x, 3)
nn = tf.layers.dense(nn_2, 1, activation=None)
new_r = new_relu(x, tf.tile(tf.expand_dims(x_b, -1), [1, 3]))
with tf.Session() as sess:
sess.run(tf.initializers.global_variables())
sess.run(new_r, feed_dict={x: np.random.rand(100, 3), x_b: np.random.rand(100)})
new_relu_test()
编辑 2:
使用 conv2d
import numpy as np
import tensorflow as tf
def new_relu(x, k=0.2):
part_1 = tf.to_float(tf.math.less_equal(0.0, x))
part_2 = tf.to_float(tf.math.logical_and(tf.math.less_equal(-1.0, x), tf.math.less(x, 0.0)))
part_3 = tf.to_float(tf.math.less(x, -1.0))
return part_1*x + part_2*x*k #+ part_3*0
def new_relu_test():
# create data
x = tf.random_normal([10])*10000
y = new_relu(x)
with tf.Session():
diff = tf.test.compute_gradient_error(x, [10], y, [10])
print(diff)
# use in dense
x = tf.placeholder(shape=[None, 28, 28, 3], dtype=tf.float32)
conv1_weights = tf.get_variable("weight",[3,3,3,32],initializer=tf.truncated_normal_initializer(stddev=0.1))
conv1_biases = tf.get_variable("bias", [32], initializer=tf.constant_initializer(0.0))
conv1 = tf.nn.conv2d(x, conv1_weights, strides=[1, 1, 1, 1], padding='SAME')
relu1 = new_relu(tf.nn.bias_add(conv1, conv1_biases))
with tf.Session() as sess:
sess.run(tf.initializers.global_variables())
sess.run(relu1, feed_dict={x: np.random.rand(100, 28, 28, 3)})
new_relu_test()
