我将 Selenium for Python 与 PhantomJS Ghost Driver 一起使用，以便单击 href 中包含 Javascript 的链接，例如来自 this 的链接。关联。我可以将链接作为一个元素很好地获取，但是当我尝试单击它时，出现了问题。这是一些代码(注意 - url 是一个列表，其中第一个元素是 Jscript 链接，第二个是链接文本)
def get_jscript_down(self,url):
driver = webdriver.PhantomJS()
print(self.exact_url)
driver.get(self.exact_url)
elements = driver.find_elements_by_tag_name("a")
for ele in elements:
if ele.text == url[1].encode("utf-8").replace(" "," "):
break
ele.click()
print("Cannot yet download %s" % url)
return False
除 ele.click() 外，一切正常。当我执行它时，我得到一个丑陋的 WebDriverException。
selenium.common.exceptions.WebDriverException: 消息:u'Error Message =>\'Click failed: ReferenceError: Can\'t find variable: __doPostBack\'\n caused by Request => {"headers":{"Accept": "application/json","Accept-Encoding":"identity","Connection":"close","Content-Length":"81","Content-Type":"application/json;charset=UTF-8 ","Host":"127.0.0.1:34441","User-Agent":"Python-urllib/2.6"},"httpVersion":"1.1","method":"POST","post":"{\"sessionId\":\"71c20b50-ca21-11e2-a03c-f58c49e5a1bc\",\"id\":\":wdc:1370025577147\"}","url":"/click","urlParsed":{" anchor ":"","查询":"","文件":"点击","目录":"/","路径":"/点击","相对":"/点击", "端口":"","主机":"","密码":"","用户":"","用户信息":"","权限":"","协议(protocol)":"","source":"/click","queryKey":{},"chunks":["click"]},"urlOriginal":"/session/71c20b50-ca21-11e2-a03c-f58c49e5a1bc/element/%3Awdc%3A1370025577147/点击”}' ;屏幕截图:可通过屏幕获得
我不太确定这次点击失败的原因。据我所知，以这种方式使用 click 应该没问题。下面是堆栈跟踪的相关部分(从事情开始崩溃之前到结束)
line 283, in get_jscript_down
ele.click()
File "/usr/local/lib/python2.6/dist-packages/selenium/webdriver/remote/webelement.py", line 54, in click
self._execute(Command.CLICK_ELEMENT)
File "/usr/local/lib/python2.6/dist-packages/selenium/webdriver/remote/webelement.py", line 228, in _execute
return self._parent.execute(command, params)
File "/usr/local/lib/python2.6/dist-packages/selenium/webdriver/remote/webdriver.py", line 165, in execute
self.error_handler.check_response(response)
File "/usr/local/lib/python2.6/dist-packages/selenium/webdriver/remote/errorhandler.py", line 158, in check_response
raise exception_class(message, screen, stacktrace)
任何想法将不胜感激。我很困惑。
请您参考如下方法:
我在 this page 上单击“Privatperson”时遇到同样的错误.该按钮的 ID 为“btnSelectB2C”。我最终做的是在元素上使用提交:
driver.find_element(:id, 'btnSelectB2C').submit
(这是 Ruby 代码，但我认为如果它适用于您的情况，它应该很容易适应。)
