python之beautiful Soup中python响应报错如何继续

我做了一个网络爬虫，它从一个文本文件中获取数千个 Urls，然后爬取该网页上的数据。
现在它有很多网址；一些网址也被破坏了。
所以它给了我错误:

Traceback (most recent call last):   
File "C:/Users/khize_000/PycharmProjects/untitled3/new.py", line 57, in <module>  
 
crawl_data("http://www.foasdasdasdasdodily.com/r/126e7649cc-sweetssssie-pies-mac-and-cheese-recipe-by-the-dr-oz-show")   
 
  File "C:/Users/khize_000/PycharmProjects/untitled3/new.py", line 18, in crawl_data    
 
 data = requests.get(url)    
 
File "C:\Python27\lib\site-packages\requests\api.py", line 67, in get    
return request('get', url, params=params, **kwargs)    
 
File "C:\Python27\lib\site-packages\requests\api.py", line 53, in request    
return session.request(method=method, url=url, **kwargs)  
 
File "C:\Python27\lib\site-packages\requests\sessions.py", line 468, in request   
 resp = self.send(prep, **send_kwargs)   
 
File "C:\Python27\lib\site-packages\requests\sessions.py", line 576, in send   
r = adapter.send(request, **kwargs)   
 
File "C:\Python27\lib\site-packages\requests\adapters.py", line 437, in send   
  raise ConnectionError(e, request=request)   
 
requests.exceptions.ConnectionError: HTTPConnectionPool(host='www.foasdasdasdasdodily.com', port=80): Max retries exceeded with url: /r/126e7649cc-sweetssssie-pies-mac-and-cheese-recipe-by-the-dr-oz-show (Caused by NewConnectionError('<requests.packages.urllib3.connection.HTTPConnection object at 0x0310FCB0>: Failed to establish a new connection: [Errno 11001] getaddrinfo failed',)) 

这是我的代码:

def crawl_data(url): 
    global connectString 
    data = requests.get(url) 
    response = str( data ) 
    if response != "<Response [200]>": 
        return 
    soup = BeautifulSoup(data.text,"lxml") 
    titledb = soup.h1.string 

但它仍然给我相同的异常或错误。

I simply want it to ignore that Urls from which there is no response and move on to the next Url.

请您参考如下方法:

您需要了解异常处理。忽略这些错误的最简单方法是用 try-except 构造包围处理单个 URL 的代码，让您的代码读起来像这样:

try: 
    <process a single URL> 
except requests.exceptions.ConnectionError: 
    pass 

这意味着如果发生指定的异常，您的程序将只执行pass(什么都不做)语句并继续下一个