python之使用双递归从列表中删除 John Wick

为了让我接管 Matrix，我首先需要从中移除 John Wick。他非常善于隐藏(很明显)，所以他把自己分成了一个列表和列表中的列表。例如:

environment = ["a", [**"j"**, "e", **"o"**], [**"h"**, **"n"**, "s",  
    **"w"**, "o"], [**"i", "c", "k"**]] 
 
target = "johnwick" 

只允许双重递归，以便从 Matrix 的列表中删除 John Wick。他不属于这里。这是我到目前为止想出的:

def no_wick(environment): 
    target = "johnwick" 
    clean_matrix = [] 
    if not environment: 
        return clean_matrix 
    elif isinstance(environment[0], list):  
 
        ??????? 
 
    elif environment[0] not in target: 
        return clean_matrix.append(environment[0]) + no_wick(environment[1:]) 
    else:  
        return no_wick(environment[1:]) 

你能帮我把约翰威克从黑客帝国中移除，而我照顾托马斯 A. 安德森吗？

请您参考如下方法:

如果我理解你是正确的，这个例子可以帮助你:

In [1]: target = 'johnwick' 
 
In [2]: environment = ['a', ['j', 'e', 'o'], ['h', 'n', 's', 'w', 'o'], ['i', 'c', 'k']] 
 
In [3]: def no_wick(l, target): 
   ...:     clear = [] 
   ...:     for x in l: 
   ...:         if isinstance(x, list): 
   ...:             x, target = no_wick(x, target) 
   ...:             clear.append(x) 
   ...:         else: 
   ...:             if target.startswith(x): 
   ...:                 target = target[1:] 
   ...:             else: 
   ...:                 clear.append(x) 
   ...:     return clear, target 
 
 
In [4]: no_wick(environment, target) 
Out[4]: (['a', ['e'], ['s', 'o'], []], '')