我有一个从用户那里获取输入值的 Django 表单。然后使用这些值对表 ResourceBase 进行查询，最终返回过滤结果列表。
由于结果可能很长，我添加了带有“上一页”和“下一页”按钮的分页功能。我的问题是，当我单击“Prev”或“Next”按钮时，表单恢复为默认值。并且所有返回的结果都没有了。我如何防止这种情况发生？
我认为当请求不是“POST”时，表单会因为“form1 = QueryForm()”而被重置。但是，由于我是 Django 和 Web 开发人员的新手，所以我很难想出一个简洁的解决方案。
在 views.py 中:
def search(request):
if request.method == "POST":
form1 = QueryForm(data=request.POST)
layer_dict = []
if form1.is_valid():
inp_ct = form1.cleaned_data['country']
q1 = ResourceBase.objects.filter(country_name__iexact=inp_ct)
for layer in q1:
down_url = 'xxxxxxx'.format(layer.title)
view_url = 'xxxxxxx'.format(layer.title)
layer_dict.append((layer.title, down_url, view_url))
layer_dict = sorted(layer_dict, key = lambda x:x[0])
paginator = Paginator(layer_dict, 10)
page = request.GET.get('page', 1)
try:
layers = paginator.page(page)
except PageNotAnInteger:
# If page is not an integer, deliver first page.
layers = paginator.page(1)
except EmptyPage:
# If page is out of range (e.g. 9999), deliver last page of results.
layers = paginator.page(paginator.num_pages)
context = {'form1': form1, 'layers': layers}
else:
form1 = QueryForm()
context = {'form1': form1}
return render(request, 'my_app/search.html', context)
在 search.html 中:
<br />
<h3>Pagination Test</h3>
<br /><br/>
<div class="row">
<div class="col-md-4">
<form method="POST">
{% csrf_token %}
<div class="form-controls">
{{ form1|as_bootstrap }}
</div>
<button class="btn btn-primary" type="submit" style="float: right;" title = "Click to search" ><i class="fa fa-search"></i></button>
</form>
<form method="GET">
<button class="btn btn-primary" type="submit" value="Reset" name="Reset" title="Reset all choices">Reset</button>
</form>
</div>
</div>
{% if layers %}
<div class="row">
<div class="col-md-8">
<div id = "search_results" >
<table class="table table-hover">
<thead>
<tr>
<th scope="col">Select</th>
<th scope="col">Layer Name</th>
<th scope="col">Download</th>
<th scope="col">View Layer</th>
</tr>
</thead>
<tbody>
{% for layer in layers %}
<tr>
<td><input class= messageCheckbox type="checkbox" name="checks" value="{{layer.1}}"/></td>
<td>{{layer.0}}</td>
<td><a href="{{layer.1}}" target="_blank"> Download Layer </a></td>
<td><input class="btn btn-primary" onclick="window.open('{{layer.2}}')" id="view" type="button" name="view" value="View"></td>
</tr>
{% endfor %}
<tr>
<td><input type="checkbox" onClick="toggle(this, 'checks')"/> Select All</td>
<td></td>
<td></td>
<td></td>
</tr>
</tbody>
</table>
<button class="btn btn-primary" type="button" name="download" style="float: left;" onClick= "open_all_links();">Download Selected</button>
</div>
<div class="a_pagination" align="right">
<span class="step-links">
{% if layers.has_previous %}
<a class="btn btn-primary btn-sm" name="prev_page" href="?page={{ layers.previous_page_number }}" role="button">Prev.</a>
{% endif %}
<span class="current" style ="color:#2C689C;font-size:16px;padding:8px;">
page {{ layers.number }} of {{ layers.paginator.num_pages }}
</span>
{% if layers.has_next %}
<a class= "btn btn-primary btn-sm" href="?page={{ layers.next_page_number }}" role="button">Next</a>
{% endif %}
</span>
</div>
</div>
</div>
{% endif %}
<script type="text/javascript" >
.......
</script>
请您参考如下方法:
您不需要使用POST 方法 将您的参数传递给您的views.py。 按照下面的示例重写您的 view 和 html form。 这里有一个简单的表格供用户输入搜索词:
<form method="get" action="">
<input type="text" name="search4" class="search_input" placeholder="Search" required="required">
<input type="submit" value="Search">
</form>
下一步是检查 views.py 中的输入，我们将输入标记命名为 name="search4" 所以我们检查是否有在我们的 views.py 中使用此代码在我们的表单中输入:
from django.db.models import Q
from django.core.paginator import Paginator
def search(request):
query = request.GET.get("search4")
if query:
queryset = ResourceBase.objects.objects.all() # this will get all of your object of your model
results = queryset.filter(Q(country_name__iexact=query)).all()
number_of_objects = results.count() # get the exact number of object to show in your html file
paginator = Paginator(results, 12) # Show 12 contacts per page
page_var = 'page' # this will use for pagination in your html file
page = request.GET.get(page_var) # this will use for pagination in your html file
contacts = paginator.get_page(page) # send only 12 object to your html file to show to user
context = {
"items": contacts,
"key": str(query),
'page': page_var,
"number_of_objects": number_of_objects,
}
return render(request=request, template_name='search.html', context=context, content_type=None, status=None,
using=None)
else:
... # if user didn't enter anything to search
在您的数据库中获取并搜索用户输入后，您应该在您的 search.html 文件中将其显示给用户，如下所示:
{% for item in items %}
<div>
<div>
<div class="product_title">{{ item.title }}</div> # show the part that you want the users to see
... # rest of your item parts to show
</div>
</div>
{% endfor %}
<div class="pagination">
<span class="step-links">
{% if items.has_previous %} # check the pagination that if there is perivious pages
<a href="?{{ page }}=1">« first</a>
<a href="?{{ page }}={{ items.previous_page_number }}">previous</a>
{% endif %}
<span class="current">
Page {{ items.number }} of {{ items.paginator.num_pages }} # example of result : Page 1 of 13
</span>
{% if items.has_next %}
<a href="?{{ page }}={{ items.next_page_number }}"</a> # check the pagination that if there is any next or perivious pages
<a href="?{{ page }}={{ items.paginator.num_pages }}">last »</a> # a link to last page
{% endif %}
</span>
{{ pagination }}
这是一个带有 Paginator 的基本搜索页面，如果您需要任何进一步的帮助或问题，我很乐意提供帮助。
