python之如何仅显示 django 模板中列表中的不同值

def avail_times(request, club_id): 
    club = get_object_or_404(Club,pk=club_id) 
    open_slots = Opening.objects.filter(club_id=club_id, day=datetime.date.today(), reservation ='Open') 
    return render_to_response('reserve/templates/avail_times.html', {'club':club, 'open_slots':open_slots}) 
 
 
<ul> 
{% for slot in open_slots %} 
    <li> {{slot }} on Court {{slot.court}} </li> 
{% endfor %} 
</ul> 
 
 
from django.db import models 
import datetime 
 
class Club(models.Model): 
    establishment = models.CharField(max_length=200) 
    address = models.CharField(max_length=200) 
    def __unicode__(self): 
        return self.establishment 
 
class Day(models.Model): 
    club = models.ForeignKey(Club) 
    day = models.DateField('day') 
    def __unicode__(self): 
        return unicode(self.day) 
 
class Court(models.Model): 
    club = models.ForeignKey(Club) 
    day = models.ForeignKey(Day) 
    court = models.IntegerField(max_length=200) 
    def __unicode__(self): 
        return unicode(self.court) 
 
class Opening(models.Model): 
    club = models.ForeignKey(Club) 
    day = models.DateField('date') 
    court = models.ForeignKey(Court) 
    slot = models.TimeField('slot') 
    reservation = models.CharField(max_length=200) 
    def __unicode__(self): 
        return unicode(self.slot) 

在上面的模板中，我只想显示一个不同的“时段”时间。因此，即使早上 6 点出现在“court 1”和“court 2”下，我也希望它通过模板只显示一次。我该怎么做？

请您参考如下方法:

内置regroup过滤器正是这样做的。