Python:匹配某些术语的字符串

我有一个推文列表，我必须从中选择包含“促销”、“折扣”或“优惠”等术语的推文。此外，我需要通过识别诸如“%”、“Rs.”、“$”等内容来查找宣传某些交易(如折扣)的推文。我对正则表达式一无所知，而且文档也无济于事。这是我的代码。这很糟糕，但请原谅

import pymongo 
import re 
import datetime 
client  = pymongo.MongoClient() 
db = client .PWSocial 
fourteen_days_ago = datetime.datetime.utcnow() - datetime.timedelta(days=14) 
id_list = [57947109, 183093247, 89443197, 431336956] 
ar1 = [" deal "," deals ", " offer "," offers " "discount", "promotion", " sale ", " inr", " rs", "%", "inr ", "rs ", " rs."] 
def func(ac_id): 
    mylist = [] 
    newlist = [] 
    tweets = list(db.tweets.find({'user_id' : ac_id, 'created_at': { '$gte': fourteen_days_ago }})) 
    for item in tweets: 
        data = item.get('text') 
        data = data.lower() 
        data = data.split() 
        flag = 0 
        if set(ar1).intersection(data): 
            flag = 1 
        abc = [] 
        for x in ar1: 
            for y in data: 
                    if re.search(x,y): 
                        abc.append(x) 
                        flag = 1 
                        break 
        if flag == 1: 
            mylist.append(item.get('id')) 
            newlist.append(abc) 
    print mylist 
    print newlist 
for i in id_list: 
    func(i) 

这段代码没有给我任何正确的结果，而且作为正则表达式的菜鸟，我不知道它有什么问题。谁能建议更好的方法来完成这项工作？感谢您的帮助。

请您参考如下方法:

我的第一个建议——学习正则表达式，它赋予你无限的文本处理能力。

但是，为了给你一些可行的解决方案(并作为进一步探索的起点)试试这个:

import re 
 
re_offers = re.compile(r''' 
    \b  # Word boundary 
        (?:  # Non capturing parenthesis 
            deals?  # Deal or deals 
            |  # or ... 
            offers?  # Offer or offers 
            | 
            discount 
            | 
            promotion 
            | 
            sale 
            | 
            rs\.?  # rs or rs. 
            | 
            inr\d+  # INR then digits 
            | 
            \d+inr  # Digits then INR 
        )  # And group 
    \b  # Word boundary 
    |  # or ... 
    \b\d+%  # Digits (1 or more) then percent 
    | 
    \$\d+\b  # Dollar then digits (didn't care of thousand separator yet) 
    ''', 
    re.I|re.X)  # Ignore case, verbose format - for you :) 
 
abc = re_offers.findall("e misio $1 is inr123 discount 1INR a 1% and deal") 
print(abc)