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python之计算代码运行 Python 的时间

2025年05月04日17mfryf

我如何知道 Python 代码的执行时间(以微秒为单位)?我已经尝试了 time.time 和 timeit.timeit 但我无法获得良好的输出

请您参考如下方法:

试试这个,

import time 
def main(): 
    print [i for i in range(0,100)] 
     
start_time = time.clock() 
main() 
print time.clock() - start_time, "seconds" 

输出:

[0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, 52, 53, 54, 55, 56, 57, 58, 59, 60, 61, 62, 63, 64, 65, 66, 67, 68, 69, 70, 71, 72, 73, 74, 75, 76, 77, 78, 79, 80, 81, 82, 83, 84, 85, 86, 87, 88, 89, 90, 91, 92, 93, 94, 95, 96, 97, 98, 99] 
0.00255163020819 seconds 

更新

不要忘记导入时间

将此行 start_time = time.clock() 放在您的代码之前并放置此

在代码末尾打印 time.clock() - start_time, "seconds"。

更新

# Top Of script file. 
def main(): 
        print [i for i in range(0,100)] 
 
start_time = time.clock() 
#YOUR CODE HERE - 1 
 
main() 
 
#YOUR CODE HERE - N 
print time.clock() - start_time, "seconds" 

你也可以写装饰器来测量时间,

import time 
 
 
def dec(func): 
    def wrapper(*args, **kwargs): 
        start = time.time() 
        func(*args, **kwargs) 
        end = time.time() 
        print(end - start) 
    return wrapper 
 
 
@dec 
def test(): 
    for i in range(10): 
        pass 
 
 
test() 
# output shows here