我正在尝试编写一个 python 脚本来计算以下系列:
1-x+x^2-x^3+x^4...
如果有人可以提供一些关于如何使这项工作适用于任何 n 值的指导，我将不胜感激？
到目前为止，我只能通过对所有操作进行硬编码来做到这一点 :D
提前致谢!
我目前的解决方案:
def seriesrun(x,n):
ncurrent = 0
total = 1
while ncurrent <= n:
if ncurrent == 0:
ncurrent = ncurrent + 1
total = total * 1
print(ncurrent, total)
elif ncurrent == 1:
ncurrent = ncurrent + 1
total = total - x
print(ncurrent, total)
elif ncurrent == 2:
ncurrent = ncurrent + 1
total = total + x**2
print(ncurrent, total)
elif ncurrent == 3:
ncurrent = ncurrent + 1
total = total - x**3
print(ncurrent, total)
elif ncurrent == 4:
ncurrent = ncurrent + 1
total = total + x**4
print(ncurrent, total)
elif ncurrent == 5:
ncurrent = ncurrent + 1
total = total - x**5
print(ncurrent, total)
return total
x = int(input('What is your starting x value?\n'))
n = 5
# n = int(input('How far should the series go?'))
# the current n position you are at...
print('Final answer is: '+str(seriesrun(x,n)))
请您参考如下方法:
你可以试试:
series = 0
pow = 0
while True:
series += (-1*x)**pow
pow += 1
这是一个无限循环，因此您可以添加退出条件。
编辑:忘记交替符号
