python之如何在 python 中提取同一类中的多个链接

我想从以下代码中提取同一个 div 类中的所有链接:

<div class='page-numbers clearfix'><span class='current'> 
1</span><a href='https://www.example.com/blog/author/abc/page/2/' class='inactive'> 
2</a><a href='https://www.example.com/blog/author/abc/page/3/' class='inactive'> 
3</a><a href='https://www.example.com/blog/author/abc/page/4/' class='inactive'> 
4</a></div> 

我试过:

from bs4 import BeautifulSoup 
 
html="<div class='page-numbers clearfix'><span class='current'>1</span><a href='https://www.example.com/blog/author/abc/page/2/' class='inactive'>2</a><a href='https://www.example.com/blog/author/abc/page/3/' class='inactive'>3</a><a href='https://www.example.com/blog/author/abc/page/4/' class='inactive'>4</a></div> 
" 
 
soup = BeautifulSoup(html, "html.parser") 
for i in soup.find_all('div', {'class': 'page-numbers clearfix'}): 
    link= i.find('a', href=True) 
    print(link['href']) 

但这似乎不起作用。我需要的输出是:

https://www.example.com/blog/author/abc/page/2/ 
 
https://www.example.com/blog/author/abc/page/3/ 
 
https://www.example.com/blog/author/abc/page/4/ 

请您参考如下方法:

您还必须使用 find_all 来查找 a 标签。下面的代码工作正常。

from bs4 import BeautifulSoup as bs 
 
stra = """ 
<div class='page-numbers clearfix'><span class='current'> 
1</span><a href='https://www.example.com/blog/author/abc/page/2/' class='inactive'> 
2</a><a href='https://www.example.com/blog/author/abc/page/3/' class='inactive'> 
3</a><a href='https://www.example.com/blog/author/abc/page/4/' class='inactive'> 
4</a></div> 
""" 
soup = bs(stra, 'html.parser') 
for i in soup.find_all('div', {'class': 'page-numbers clearfix'}): 
    links = i.find_all('a', href=True) 
    for link in links: 
        print(link['href']) 
 

输出:

https://www.example.com/blog/author/abc/page/2/ 
https://www.example.com/blog/author/abc/page/3/ 
https://www.example.com/blog/author/abc/page/4/