python之只能将元组(不是 "unicode")连接到元组

我正在使用 Django 1.5.4

我是 Django 的新手，我试图显示通过管理面板上传的图片，但不幸的是，图片源代码中的 url 字段是空，如果我更改 { { article.image.url }} 到 {{ article.image }}，图片 url 显示为

<img src="media/abyss.jpg" alt="" height="450"/>  

当我点击图片链接时，它显示

TypeError at /media/abyss.jpg 
can only concatenate tuple (not "unicode") to tuple 

请帮助我。

Settings.py 文件

 MEDIA_ROOT = (os.path.join(os.path.dirname(__file__), '..', 'media').replace('\\','/'),) 
 MEDIA_URL = '/media/' 

模型.py 文件

class Article(models.Model): 
    title = models.CharField(max_length=255) 
    slug = models.SlugField(unique=True, max_length=255) 
    description = models.TextField() 
    content = models.TextField() 
    published = models.BooleanField(default=True) 
    image = models.ImageField(upload_to='media', blank=True) 
    created = models.DateTimeField(auto_now_add=True) 
 
 
   def __unicode__(self): 
       return u'%s' % self.title 
 
   class Meta: 
      ordering = ['-created'] 
 
   def get_absolute_url(self): 
      return reverse('blog.views.article', args=[self.slug]) 

网址.py

urlpatterns = patterns('', 
                       url(r'^admin/', include(admin.site.urls)), 
                       url(r'^$', 'blog.views.index'), 
                       url(r'^blog/(?P<slug>[\w\-]+)/$', 'blog.views.article'), 
                       url(r'^(.*)$', 'django.views.static.serve', {'document_root': settings.MEDIA_ROOT}), 
                       ) 

index.html

{% extends "blog/base.html" %} 
 
{% block content %} 
    <h1>PyStack</h1> 
 
    <div> 
        {% for article in articles %} 
            <img src="{{ article.image.url }}" alt="" height="450"/> 
            <h2><a href="{{ article.get_absolute_url }}">{{ article.title|capfirst }}</a></h2> 
            <p>{{ article.description }}</p> 
            <hr/> 
        {% endfor %} 
    </div> 
 
{% endblock %} 

请您参考如下方法:

MEDIA_ROOT 应该是字符串而不是元组:

MEDIA_ROOT = os.path.join(os.path.dirname(__file__), '..', 'media').replace('\\','/') 

尾随逗号使其成为一个元组:

>>> x = (1,) 
>>> type(x) 
<type 'tuple'> 
>>> x + u'foo' 
Traceback (most recent call last): 
    x + u'foo' 
TypeError: can only concatenate tuple (not "unicode") to tuple