python之如何将 kwargs 传递给 python 中的另一个 kwargs

def a(**akwargs): 
    def b(bkwargs=akwargs): 
        # how to not only use akwargs defaultly,but also define bkwargs by 
        # myself? 
        print bkwargs 
    return b 

如果我想实现下面的功能。我该如何处理上面的代码？

>>>a(u='test')() 
{'u': test} 
 
>>>a(u='test')(u='test2') 
{'u': test2} 

请您参考如下方法:

有点不清楚你想要什么，但我认为这是诀窍:

def a(**akwargs): 
    def b(bkwargs=akwargs, **kwargs): 
        # how to not only use akwargs defaultly,but also define bkwargs by 
        # myself? 
        if not bkwargs: 
            bkwargs = kwargs 
        else: 
            # it depends what you want here (merge or replace?), but probably 
            # something like bkwargs.update(kwargs) or kwargs.update(bkwargs) 
    return b