Python 无法保存名称前带斜杠的文件

with open('/tests/testDict.pickle','wb') as fp: print 'to terminal' 

上面的内容有什么问题让我发疯并给了我以下内容:

--------------------------------------------------------------------------- 
IOError                                   Traceback (most recent call last) 
<ipython-input-17-fe5a4a9f361c> in <module>() 
----> 1 with open('/tests/testDict.pickle','wb') as fp: print 'to terminal' 
 
IOError: [Errno 2] No such file or directory: '/tests/testDict.pickle' 

如果前面没有斜杠，我会得到:

with open('tests/testDict.pickle','wb') as fp: print 'to terminal' 
to terminal 

我在 OS X 中有以下目录结构:

$ ls 
cp1.py           cp1_pdftest.jpg  random/          tests/ 

请您参考如下方法:

"/tests/" 上的前导斜杠强制路径为绝对路径，即使您正在这样做也是如此

os.path.join(os.getcwd(), "/tests/") 

所以你需要做

os.path.join(os.getcwd(), "tests/") 

来自os.path.join文档:

os.path.join(path, *paths)

Join one or more path components intelligently. The return value is the concatenation of path and any members of *paths with exactly one directory separator (os.sep) following each non-empty part except the last, meaning that the result will only end in a separator if the last part is empty. If a component is an absolute path, all previous components are thrown away and joining continues from the absolute path component.