我有一个包含许多部分的文件，如下所示:
[40.742742,-73.993847]
[40.739389,-73.985667]
[40.74715499999999,-73.97992]
[40.750573,-73.988415]
[40.742742,-73.993847]
[40.734706,-73.991915]
[40.736917,-73.990263]
[40.736104,-73.98846]
[40.740315,-73.985263]
[40.74364800000001,-73.993353]
[40.73729099999999,-73.997988]
[40.734706,-73.991915]
[40.729226,-74.003463]
[40.7214529,-74.006038]
[40.717745,-74.000389]
[40.722299,-73.996634]
[40.725291,-73.994413]
[40.729226,-74.003463]
[40.754604,-74.007836]
[40.751289,-74.000649]
[40.7547179,-73.9983309]
[40.75779,-74.0054339]
[40.754604,-74.007836]
我需要将这些部分中的每一个部分作为坐标对列表读取(每个部分由一个额外的 \n 分隔)。
在我拥有的一个类似文件中(除了没有额外的换行符外，其他文件相同)，我从整个文件中绘制一个多边形。我可以使用以下代码读取坐标并在 matplotlib 中绘制它:
mVerts = []
with open('Manhattan_Coords.txt') as f:
for line in f:
pair = [float(s) for s in line.strip()[1:-1].split(", ")]
mVerts.append(pair)
plt.plot(*zip(*mVerts))
plt.show()
我怎样才能完成同样的任务，除了多于 1 个多边形，我的文件中的每个多边形由一个额外的换行符分隔？
请您参考如下方法:
这是我个人最喜欢的将文件“分块”为由空格分隔的内容组的方法:
from itertools import groupby
def chunk_groups(it):
stripped_lines = (x.strip() for x in it)
for k, group in groupby(stripped_lines, bool):
if k:
yield list(group)
我建议 ast.literal_eval 将列表的字符串表示形式转换为实际的 Python 列表:
from ast import literal_eval
with open(filename) as f:
result = [[literal_eval(li) for li in chunk] for chunk in chunk_groups(f)]
给予:
result
Out[66]:
[[[40.742742, -73.993847],
[40.739389, -73.985667],
[40.74715499999999, -73.97992],
[40.750573, -73.988415],
[40.742742, -73.993847]],
[[40.734706, -73.991915],
[40.736917, -73.990263],
[40.736104, -73.98846],
[40.740315, -73.985263],
[40.74364800000001, -73.993353],
[40.73729099999999, -73.997988],
[40.734706, -73.991915]],
[[40.729226, -74.003463],
[40.7214529, -74.006038],
[40.717745, -74.000389],
[40.722299, -73.996634],
[40.725291, -73.994413],
[40.729226, -74.003463],
[40.754604, -74.007836],
[40.751289, -74.000649],
[40.7547179, -73.9983309],
[40.75779, -74.0054339],
[40.754604, -74.007836]]]
