我正在寻找一种方法，让函数根据执行时间长短采取行动。例如，我的函数会连续循环直到 5 秒过去，在这种情况下它会立即返回。有什么建议吗？
请您参考如下方法:
你看过time.clock()了吗？ ？
time.clock()On Unix, return the current processor time as a floating point number expressed in seconds. The precision, and in fact the very definition of the meaning of “processor time”, depends on that of the C function of the same name, but in any case, this is the function to use for benchmarking Python or timing algorithms.
On Windows, this function returns wall-clock seconds elapsed since the first call to this function, as a floating point number, based on the Win32 function QueryPerformanceCounter(). The resolution is typically better than one microsecond.
在 Windows 上使用“time.clock()”测量时间:
>>> import time
>>> def measure():
... t0 = time.clock()
... time.sleep(3)
... return time.clock() - t0
...
>>> measure()
2.9976609581514113
>>>
