mylist = [{"a" : 1, " b" : 2}, {"c" : 1, "d" :2}]
我的 list 是这样的。我将如何删除包含键“a”的整个字典?
请您参考如下方法:
您可以使用 list comprehension 使用 dict 来创建一个新列表,而无需 'a' 键,如下所示:
>>> mylist = [{"a" : 1, " b" : 2},{"c" : 1, "d" :2}]
>>> [d for d in mylist if 'a' not in d]
[{'c': 1, 'd': 2}]
如果必须从原始列表中删除元素,那么您可以这样做:
>>> mylist = [{"a" : 1, " b" : 2},{"c" : 1, "d" :2}]
# v Iterate over the copy of the list,
# v so that the change in index after the
# v deletion of elements in the list won't
# v impact the future iterations
>>> for i, d in enumerate(list(mylist)):
... if 'a' in d:
... del mylist[i]
...
>>> mylist
[{'c': 1, 'd': 2}]
