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Python urllib2 URLError 异常

2025年05月04日11mate10pro

我之前在 Windows XP 机器上安装了 Python 2.6.2 并运行以下代码:

import urllib2 
import urllib 
 
page = urllib2.Request('http://www.python.org/fish.html') 
urllib2.urlopen( page ) 

我收到以下错误。

Traceback (most recent call last):<br> 
  File "C:\Python26\test3.py", line 6, in <module><br> 
    urllib2.urlopen( page )<br> 
  File "C:\Python26\lib\urllib2.py", line 124, in urlopen<br> 
    return _opener.open(url, data, timeout)<br> 
  File "C:\Python26\lib\urllib2.py", line 383, in open<br> 
    response = self._open(req, data)<br> 
  File "C:\Python26\lib\urllib2.py", line 401, in _open<br> 
    '_open', req)<br> 
  File "C:\Python26\lib\urllib2.py", line 361, in _call_chain<br> 
    result = func(*args)<br> 
  File "C:\Python26\lib\urllib2.py", line 1130, in http_open<br> 
    return self.do_open(httplib.HTTPConnection, req)<br> 
  File "C:\Python26\lib\urllib2.py", line 1105, in do_open<br> 
    raise URLError(err)<br> 
URLError: <urlopen error [Errno 11001] getaddrinfo failed><br><br><br> 

请您参考如下方法:

import urllib2 
response = urllib2.urlopen('http://www.python.org/fish.html') 
html = response.read() 

你做错了。