我有一个 list ，
L = [['First', 'Last', 'GPA', 'Major', 'Drops'],
['Jane', 'Doe', '3.5', 'CS', '2'], ['Joe', 'Doe', '2.0', 'CpE', '0'],
['Todd', 'Brown', '3.88', 'CS', '5'],
['Mike', 'Smith', '3.88', 'CS', '5']]
我必须将其打印在表格中，例如:
--------------------------------------------------------
| First| Last| GPA| Major| Drops|
--------------------------------------------------------
| Jane| Doe| 3.50| CS| 2|
| Joe| Doe| 2.00| CpE| 0|
| Todd| Brown| 3.88| CS| 5|
| Mike| Smith| 3.88| CS| 5|
到目前为止我的代码是:
L = [['First', 'Last', 'GPA', 'Major', 'Drops'],
['Jane', 'Doe', '3.5', 'CS', '2'],
['Joe', 'Doe', '2.0', 'CpE', '0'],
['Todd', 'Brown', '3.88', 'CS', '5'],
['Mike', 'Smith', '3.88', 'CS', '5']]
count1 = 1
while count1 < len(L):
L[count1][2] = float(L[count1][2])
L[count1][4] = int(L[count1][4])
count1 += 1
h_line = 56 * '-'
first_line = "|"
print (h_line)
s = " "
w = 10
for i in range(len(L[0])):
str1 = (s*(w - len(L[0][i])) + "%s|" % L[0][i])
first_line = first_line + str1
print(first_line)
print(h_line)
a = 1
while a < len(L):
second_line = "|"
for j in range (len(L[a])):
if type(L[a][j]) == str :
str2 = (s*(w - len(L[a][j])) + ("%s|" % L[a][j]))
second_line = second_line + str2
elif type(L[a][j]) == float :
str2 = (s*(w-4) + ("%.2f|" % L[a][j]))
second_line = second_line + str2
elif type(L[a][j]) == float :
str2 = (s*(w-1) + ("%i|" % L[a][j]))
second_line = second_line + str2
print (second_line)
a = a + 1
print (h_line)
但我的输出看起来像:
--------------------------------------------------------
| First| Last| GPA| Major| Drops|
--------------------------------------------------------
| Jane| Doe| 3.50| CS|
| Joe| Doe| 2.00| CpE|
| Todd| Brown| 3.88| CS|
| Mike| Smith| 3.88| CS|
--------------------------------------------------------
我不明白我做错了什么。伙计们，帮帮我!
请您参考如下方法:
天哪，这是错误的解决方法!!!使用 string formatting
L = [['First', 'Last', 'GPA', 'Major', 'Drops'],
['Jane', 'Doe', '3.5', 'CS', '2'], ['Joe', 'Doe', '2.0', 'CpE', '0'],
['Todd', 'Brown', '3.88', 'CS', '5'],
['Mike', 'Smith', '3.88', 'CS', '5']]
def display_table(rows):
template = "|{:>10}|{:>10}|{:>10}|{:>10}|{:>10}|"
horiz_rule = "-" * 56
header = rows[0]
print(horiz_rule)
print(template.format(*header))
print(horiz_rule)
for row in rows[1:]:
print(template.format(*row))
print(horiz_rule)
display_table(L)
如果您需要能够以编程方式分配列宽，您可以使用额外的 { 和 } 来转义外部格式，例如
template = "|{{:>{0}}}".format(some_width) * num_columns + "|"
## if some_width is 10 and num_columns is 5,
## results in the same template as above. Then you can do:
horiz_rule = 1 + some_width * (num_columns + 1)
作为一个工作示例，也许您想将每列扩展到至少 10 个空格，但又想对齐到该列中最长的元素加 1。
def display_table(rows):
# might want a sanity check here to make sure the table is square
num_columns = len(rows)
template = "|{{:>{}}}" * len(rows[0]) + "|"
header = rows[0]
# zip(*iterable) is a good recipe for aligning columnwise
column_lengths = [max(10, max(map(len, col)) + 1) for col in zip(*rows)]
finished_template = template.format(*column_lengths)
hr = "-" * (sum(column_lengths) + num_columns + 1)
print(hr)
print(finished_template.format(*header))
print(hr)
for row in rows[1:]:
print(finished_template.format(*row))
print(hr)
display_table(L)
结果:
--------------------------------------------------------
| First| Last| GPA| Major| Drops|
--------------------------------------------------------
| Jane| Doe| 3.5| CS| 2|
| Joe| Doe| 2.0| CpE| 0|
| Todd| Brown| 3.88| CS| 5|
| Mike| Smith| 3.88| CS| 5|
--------------------------------------------------------
或者，如果您添加姓氏为“SomeReallyLongName”的学生:
L.append(['Foo','SomeReallyLongName','2.0','Mus','10'])
display_table(L)
## OUTPUT
------------------------------------------------------------------
| First| Last| GPA| Major| Drops|
------------------------------------------------------------------
| Jane| Doe| 3.5| CS| 2|
| Joe| Doe| 2.0| CpE| 0|
| Todd| Brown| 3.88| CS| 5|
| Mike| Smith| 3.88| CS| 5|
| Foo| SomeReallyLongName| 2.0| Mus| 10|
------------------------------------------------------------------
看起来最后一位在计算水平规则时有一个小差错。它对我来说看起来不错，但显然它关闭了(一个!)我将把它压扁作为读者的练习。
