有没有办法按特定顺序测试多个字符串？像这样:
if str.find(["who", "are", "you"], "who the heck are you") != -1:
Print("I AM JOE")
请您参考如下方法:
逐字测试，检查每个关键字是否包含在前一个关键字之后。
def find_in_order(text, words):
tokens = text.split()
start = 0
for word in words:
try:
start = tokens.index(word, start) + 1
except:
return False
return True
测试:
>>> find_in_order("who the hell are you", ["who", "are", "you"])
True
>>> find_in_order("who the hell is you", ["who", "are", "you"])
False
>>> find_in_order("you who the hell are you", ["who", "are", "you"])
True
>>> find_in_order("who bare bayou", ["who", "are", "you"])
False
>>> find_in_order("who are you", ["who", "are", "are", "you"])
False
或者使用不在空格处拆分的变体，因此 who bare byou 将通过:
def find_in_order(text, words):
start = 0
for word in words:
try:
start = text.index(word, start) + len(word)
except:
return False
return True
