这是我的代码:
import urllib2
from bs4 import BeautifulSoup
url = "http://www.sec.gov/Archives/edgar/data/1288776/000119312512312575/goog-20120630.xml"
req = urllib2.Request(url, "r")
response = urllib2.urlopen(req)
xml = response.read()
soup = BeautifulSoup(xml, features="xml")
print soup.prettify()
输出仅显示来自目标的前几行 XML:
>>>
<?xml version="1.0" encoding="utf-8"?>
<!-- EDGAR Online I-Metrix Xcelerate Instance Document, based on XBRL 2.1 http://www.edgar-online.com/ -->
<!-- Version: 6.17.6 -->
<!-- Round: 8321e8af-cc4a-498e-a38d-da694ed77a41 -->
<!-- Creation date: 2012-07-24T16:17:46Z -->
<xbrl xmlns="http://www.xbrl.org/2003/instance" xmlns:country="http://xbr" xmlns:iso4217="http://www.xbrl.org/2003/iso4217" xmlns:xbrll="http://www.xbrl.org/2003/linkbase" xmlns:xlink="http://www.w3.org/1999/xlink" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"/>
关于如何提取所有 XML 的任何想法?
请您参考如下方法:
你试过用开瓶器吗?
import urllib2
from BeautifulSoup import BeautifulSoup
url = "http://www.sec.gov/Archives/edgar/data/1288776/000119312512312575/goog-20120630.xml"
opener = urllib2.build_opener()
opener.addheaders = [('User-agent', 'Mozilla/5.0')]
resource = opener.open(url)
data = resource.read()
resource.close()
soup = BeautifulSoup(data)
print soup.prettify()
上面的代码对我有用。
