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python之惰性对象返回了意外的类型。管理页面身份验证时出错

2025年05月04日11oomusou

我正在尝试使用 All-Auth用于社会身份验证。

将其所需设置加载到我的应用程序 settings.py 后,我必须进入管理页面才能输入社交 token 。

我一登录管理页面。它给了我这个错误:

Environment: 
 
    Request Method: GET 
    Request URL: http://127.0.0.1:8000/admin/ 
     
    Django Version: 1.5 
    Python Version: 2.7.1 
    Installed Applications: 
    ('django.contrib.auth', 
    'django.contrib.contenttypes', 
    'django.contrib.sessions', 
    'django.contrib.sites', 
    'django.contrib.messages', 
    'django.contrib.staticfiles', 
    'django.contrib.admin', 
    'main', 
    'allauth', 
    'allauth.account', 
    'allauth.socialaccount') 
    Installed Middleware: 
    ('django.middleware.common.CommonMiddleware', 
    'django.contrib.sessions.middleware.SessionMiddleware', 
    'django.middleware.csrf.CsrfViewMiddleware', 
    'django.contrib.auth.middleware.AuthenticationMiddleware', 
    'django.contrib.messages.middleware.MessageMiddleware') 
     
    Traceback: 
    File "/Library/Python/2.7/site-packages/django/core/handlers/base.py" in get_response 
     
    response = callback(request, *callbackargs, **callback_kwargs) File "/Library/Python/2.7/site-packages/django/contrib/admin/sites.py" in wrapper 
    return self.admin_view(view, cacheable)(*args, **kwargs) File "/Library/Python/2.7/site-packages/django/utils/decorators.py" in _wrapped_view 
    response = view_func(request, *args, **kwargs) File "/Library/Python/2.7/site-packages/django/views/decorators/cache.py" in _wrapped_view_func 
    response = view_func(request, *args, **kwargs) File "/Library/Python/2.7/site-packages/django/contrib/admin/sites.py" in inner 
    return view(request, *args, **kwargs) File "/Library/Python/2.7/site-packages/django/views/decorators/cache.py" in _wrapped_view_func 
    response = view_func(request, *args, **kwargs) File "/Library/Python/2.7/site-packages/django/contrib/admin/sites.py" in index 
    app['models'].sort(key=lambda x: x['name']) File "/Library/Python/2.7/site-packages/django/utils/functional.py" in lt 
    other = other.cast() File "/Library/Python/2.7/site-packages/django/utils/functional.py" in __cast 
    return self.text_cast() File "/Library/Python/2.7/site-packages/django/utils/functional.py" in __text_cast 
    return func(*self.args, **self.kw) File "/Library/Python/2.7/site-packages/django/utils/text.py" in 
    capfirst = lambda x: x and forcetext(x)[0].upper() + force_text(x)[1:] File "/Library/Python/2.7/site-packages/django/utils/functional.py" in __wrapper 
    raise TypeError("Lazy object returned unexpected type.") 
    Exception Type: TypeError at /admin/ 
    Exception Value: Lazy object returned unexpected type 

我应该怎么做才能解决这个问题,为什么会出现异常? 任何帮助或想法将不胜感激。 亲切的问候

请您参考如下方法:

那里的函数将文本强制为什么...unicode?...在​​一种情况下是 forcetext(x),在第二种情况下是 force_text(x)。在一种情况下,它可能会返回错误消息,因为方法不存在...

艾伦