Python:子类别的正则表达式查找

正在关注 this question ，我正在考虑在字符串中包含一个层次结构。例如这是我的字符串:

sometext 
somemore    text here 
 
some  other text 
 
              course: course1 
 
some details 
TestName: test1 
some other details 
Id              Name                marks 
____________________________________________________ 
1               student1            65 
2               student2            75 
3               MyName              69 
4               student4            43 
 
some details 
TestName: test3 
some other details 
Id              Name                marks 
____________________________________________________ 
1               student1            23 
3               MyName              63 
4               student4            64 
 
 
              course: course2 
 
some details 
TestName: test2 
some other details 
Id              Name                marks 
____________________________________________________ 
1               student1            84 
2               student3            73 
 
some details 
TestName: test5 
some other details 
Id              Name                marks 
____________________________________________________ 
1               MyName              84 
2               student2            73 
 
 
              course: course4 
 
some details 
TestName: test1 
some other details 
Id              Name                marks 
____________________________________________________ 
1               student1            58 
2               student3            89 
 
some details 
TestName: test2 
some other details 
Id              Name                marks 
____________________________________________________ 
1               student1            97 
3               MyName              60 
8               student6            82 

我想获取 MyName 的详细信息。类似 (course1,test1,69),(course1,test3,63),(course2,test5,84),(course4,test2,60) 或类似输出的输出。

我无法一步完成，因此想到了这个:

import re 
eachcourse = re.split(r'course: \w+',string1) 
courselist = re.findall(r'course: (\w+)',string1) 
li =[] 
for i,course in enumerate(courselist): 
    match = re.findall(r".*?TestName: (\w+)(?:(?!\TestName\b).)*MyName\s+(\d+).*?",eachcourse[i+1],re.DOTALL) 
    li.append((course,match)) 
print li 

这给了我

[('course1', [('test1', '69'), ('test3', '63')]), ('course2', [('test5', '84')]), ('course4', [('test2', '60')])] 

有没有更好更简洁的方法？

谢谢。

请您参考如下方法:

x=re.findall(r"\bcourse: (\w+)(.*?)(?=(?:\bcourse:|$))",x,flags=re.DOTALL) 
 
 
print [[i[0]]+re.findall(r"TestName: (\w+)(?:(?!\bTestName\b).)*MyName\s*(\d+)",i[1],flags=re.DOTALL) for i in x] 

你可以试试这个，虽然格式不完全一样，但是可以用。